The equivalent conductivity of `H_(2)SO_(4)` at infinite dilution is `384 Omega^(-1) cm^(2) eq^(-1)`. If `49g H_(2)SO_(4)` per litre is present in solution and specific resistance is `18.4 Omega` then calculate the degree of dissociation.

Explanation

To solve the problem of calculating the degree of dissociation of \( H_2SO_4 \), we will follow these steps:

### Step 1: Understand the given data
- Equivalent conductivity at infinite dilution, \( \Lambda^\circ = 384 \, \Omega^{-1} \, cm^2 \, eq^{-1} \)
- Mass of \( H_2SO_4 \) per liter, \( m = 49 \, g \)
- Specific resistance, \( \rho = 18.4 \, \Omega \)

### Step 2: Calculate the equivalent weight of \( H_2SO_4 \)
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