At infinite dilution the molar conductance of `Al^(+3)` and `SO_(4)^(-2)` ion are 189 and `160 Omega^(-1) cm^(2) "mole"^(-1)` respectively. Calculate the equilvalent and molar conductance at infinite dilution of `Al_(2)(SO_(4))_(3)`.

Explanation

To solve the problem, we need to calculate the equivalent and molar conductance at infinite dilution for the compound \( Al_2(SO_4)_3 \). We will use the given molar conductance values for the ions \( Al^{3+} \) and \( SO_4^{2-} \).

### Step-by-Step Solution:

1. **Identify the Molar Conductance Values**:
- Molar conductance of \( Al^{3+} \) = 189 \( \Omega^{-1} \, cm^2 \, mole^{-1} \)
- Molar conductance of \( SO_4^{2-} \) = 160 \( \Omega^{-1} \, cm^2 \, mole^{-1} \)

...