On electrolysing `CuSO_(4)` solution in presence of `Pt`, the solution becomes colourless, blue colour of solution disappears. Why?

Explanation

`{:("At cathode",:,Cu^(2+)+2erarrCu),("At anode",:,2OH^(-)rarrH_(2)O+(1)/(2)O_(2)+2e):}`
`Cu^(2+)` ions are reduced and blue colour is due to `Cu^(2+)`.