The resistance of a `0.01N` solution of an electrolyte was found to 210 ohm at `298K` using a conductivity cell with a cell constant of `0.88 cm^(-1)`. Calculate specific conductance and equivalent conductance of solution.

Explanation

To solve the problem step by step, we will calculate the specific conductance (κ) and the equivalent conductance (Λ) of the given electrolyte solution.

### Step 1: Write down the given values
- Normality (N) = 0.01 N
- Resistance (R) = 210 Ω
- Cell constant (G*) = 0.88 cm⁻¹

### Step 2: Calculate the specific conductance (κ)
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