The conductivity of pure water in a conductivity cell with electrodes of cross-sectional area `4cm^(2)` placed at a distance `2cm` apart is `8 xx 10^(-7) S cm^(-1)`. Calculate.
(a) The resistance of water.
(b) The current that would flow through the cell under the applied potential difference of 1 volt.

Explanation

To solve the problem, we will follow these steps:

### Given Data:
- Conductivity of pure water, \( \sigma = 8 \times 10^{-7} \, \text{S cm}^{-1} \)
- Cross-sectional area of the electrodes, \( A = 4 \, \text{cm}^2 \)
- Distance between the electrodes, \( L = 2 \, \text{cm} \)
- Potential difference, \( V = 1 \, \text{V} \)

...