Calculate molar conductance for `NH_(4)OH`, given that molar conductance for `Ba(OH)_(2), BaCl_(2)` and `NH_(4)Cl` are `523.28, 280.0` and `129.8 ohm^(-1) cm^(2) mol^(-1)` respectively.

Explanation

To calculate the molar conductance for \( \text{NH}_4\text{OH} \), we will use the molar conductance values provided for \( \text{Ba(OH)}_2 \), \( \text{BaCl}_2 \), and \( \text{NH}_4\text{Cl} \).

### Step 1: Write the equations for molar conductance

1. For \( \text{Ba(OH)}_2 \):
\[ \Lambda_m(\text{Ba(OH)}_2) = \Lambda_m(\text{Ba}^{2+}) + 2 \Lambda_m(\text{OH}^-) \]
...