`E^(o)` of some elements are given as `:`
`{:(I_(2)+2e^(-)rarr 2I^(-),,,,E^(o)=0.54V),(MnO_(4)^(-)+8H^(o+)+5e^(-)rarr Mn^(2+)+4H_(2)O,,,,E^(o)=1.52V),(Fe^(3+)+e^(-)rarr Fe^(2+),,,,E^(o)=0.77V),(Sn^(4+)+2e^(-)rarr Sn^(2+),,,,E^(o)=0.1V):}`
`a.` Select the strongest reductant and weakest oxidant among these elements.
`b.` Select the weakest reductant and strongest oxidant among these elements.

Explanation

To solve the question, we need to analyze the standard reduction potentials (E°) given for each half-reaction. The stronger the reductant, the lower the E° value, and conversely, the stronger the oxidant, the higher the E° value.

### Step-by-Step Solution:

1. **List the Given Half-Reactions and Their E° Values:**
- \( I_2 + 2e^- \rightarrow 2I^- \), \( E° = 0.54 \, V \)
- \( MnO_4^- + 8H^+ + 5e^- \rightarrow Mn^{2+} + 4H_2O \), \( E° = 1.52 \, V \)
- \( Fe^{3+} + e^- \rightarrow Fe^{2+} \), \( E° = 0.77 \, V \)
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