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The measured e.m.f. at 25^(@)C for the c...

The measured e.m.f. at `25^(@)C` for the cell reaction,
`Zn(s) +XCu^(2+)._((eq))(0.1M) rarr Cu(s) ._((aq)) +Zn^(2+)(1.0M)` is 1.3 volt, calculate `E^(@)` for the cell reaction.

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To calculate the standard cell potential \( E^\circ \) for the given cell reaction, we can use the Nernst equation. Let's break down the solution step by step. ### Step 1: Write the Nernst Equation The Nernst equation is given by: \[ E_{\text{cell}} = E^\circ_{\text{cell}} - \frac{0.059}{n} \log \frac{[\text{products}]}{[\text{reactants}]} \] ...
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The cell reaction Zn(s) + Cu^(+2)rarr Zn^(+2) + Cu(s) is best represented as :

For the redox reaction Zn(s) + Cu^(2+) (0.1M) rarr Zn^(2+) (1M) + Cu(s) that takes place in a cell, E^(o)""_(cell) is 1.10 volt. E_(cell) for the cell will be:

The emf of the cell reaction Zn(s) +Cu^(2+) (aq) rarr Zn^(2+) (aQ) +Cu(s) is 1.1V . Calculate the free enegry change for the reaction. If the enthalpy of the reaction is -216.7 kJ mol^(-1) , calculate the entropy change for the reaction.

The standard emf for the cell cell reaction Zn + Cu^(2+) rarr Zn^(2+) + Cu is 1.10 volt at 25^@ C . The emf for the cell reaction when 0.1 M Cu^(2+) and 0.1 M ZN^(2+) solutions are used at 25^@ =C is .

The standard potential E^(@) for the half reactions are as : Zn rarr Zn^(2+) + 2e^(-), E^(@) = 0.76V Cu rarr Cu^(2+) +2e^(-) , E^(@) = -0.34 V The standard cell voltage for the cell reaction is ? Zn +Cu^(2) rarr Zn ^(2+) +Cu

Calculate the standard free enegry change for the reaction: Zn + Cu^(2+)(aq) rarr Cu+Zn^(2+) (aq), E^(Theta) = 1.20V

Write Nernst equation for the following cell reaction : Zn"|"Zn^(2+)(aq)"||"Cu^(2+)(aq)"|"Cu(s)

Zn(s) + Cu^(2+)(aq) rarr Zn^(2+)(aq) + Cu(s) The cell representation for the above redox reaction is

If [Zn^(2+)] is maintained at 1.0 M (i) What is the minimum (Cu^(2+)) for which the reaction Zn_((s))+Cu_((aq))^(2+) to Cu_((s))+Zn_((aq))^(2+) is still spontaneous in forward direction. (ii) Does the displacement of Cu_((aq))^(2+)" by "Zn_((s)) go to completion? E_(Zn^(2+)//Zn)^(0)=-0.76V E_(Cu^(2+)//Cu)=0.34V

Consider the following reaction, Zn(s)+Cu^(2+) (0.1 M) rarr Zn^(2+) (1 M)+Cu(s) above reaction, taking place in a cell, E_("cell")^(@) is 1.10 V. E_("cell") for the cell will be (2.303 (RT)/(F)=0.0591)

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