The cell `Pt|H_(2)(g) (1atm)|H^(+), pH = x ||` Normal calomal electrode has EMF of `0.64` volt at `25^(@)C`. The standard reduction potential of normal calomal electrode is `0.28V`. What is the `pH` of solution in anodic compartment. Take `(2.303RT)/(F) = 0.06` at `298K`.

Explanation

To solve the problem step-by-step, we will use the Nernst equation and the information provided in the question.

### Step 1: Write down the given data
- EMF of the cell, \( E_{\text{cell}} = 0.64 \, \text{V} \)
- Standard reduction potential of the normal calomel electrode, \( E^{\circ}_{\text{cell}} = 0.28 \, \text{V} \)
- Value of \( \frac{2.303RT}{F} = 0.06 \, \text{V} \) at \( 298 \, \text{K} \)

### Step 2: Write the Nernst equation
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