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20 Ml of KOH solution was titrated with ...

`20 Ml` of `KOH` solution was titrated with `0.20 M H_(2)SO_(4)` solution in a conductivity cell. The data obtained were plotted to give the graphe shown below.
The concentration of the `KOH` solution was

A

`0.3M`

B

`0.15M`

C

`0.12M`

D

`0.075M`

Text Solution

Verified by Experts

The correct Answer is:
A
`20 xx M = 0.2 xx 2xx 15 rArr M = 0.15`
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