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Molar conductance of 1M solution of weak...

Molar conductance of 1M solution of weak acid HA is 20 `ohm^(-1) cm^(2) mol^(-1)`. Find % dissocation of HA:
`(^^_(m)^(o)(H^(+)) =350 S cm^(2) mol^(-1)),(^^_(m)^(o)(A^(-)) =50 S cm^(2) mol^(-1))`

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Verified by Experts

The correct Answer is:
5

`^^_(m)^(o) (HA) = 350 +50 = 400`
`alpha =(^^_(m)^(C))/(^^_(m)^(o)) xx 100 = (20)/(400) xx100 = 5%`
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