How much volume of `10 M HCl` should be diluted with water to prepare `2.00L` of `5M HCl`?

Explanation

To solve the problem of how much volume of 10 M HCl should be diluted with water to prepare 2.00 L of 5 M HCl, we can use the dilution equation:

\[ M_1 V_1 = M_2 V_2 \]

Where:
- \( M_1 \) = initial molarity (concentration) of the solution (10 M)
- \( V_1 \) = volume of the concentrated solution we need to find
- \( M_2 \) = final molarity (concentration) of the diluted solution (5 M)
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