Calculate the molality of 1 litre solution of 93% `H_2SO_4` (weight/volume). The density of the solution is `1.84 g ml^(-1)`.

Explanation

Molarity `= ("Wt.in g" xx "density" xx 1000)/("molecular wt" xx 100) = (93 xx 1.84 xx 1000)/(98 xx 100) = 78.68 M`