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1 mole heptane (V.P = 92 mm of Hg) is mi...

1 mole heptane `(V.P = 92 mm of Hg)` is mixed with 4 mol. Octane `(V.P = 31` mm of `Hg)`, form an ideal solution. Find out the vapour pressure of solution.

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To find the vapor pressure of the solution formed by mixing 1 mole of heptane with 4 moles of octane, we will use Raoult's Law. Here’s a step-by-step solution: ### Step 1: Identify the given data - Moles of heptane (A) = 1 mole - Moles of octane (B) = 4 moles - Vapor pressure of pure heptane (Pₐ⁰) = 92 mm of Hg - Vapor pressure of pure octane (Pᵦ⁰) = 31 mm of Hg ...
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