At `88^(@)C` benzene has a vapour pressure of 900 torr and toluene has vapour pressure of 360 torr. What is the mole fraction of benzene in the mixture with toluene that will be boil at `88^(@)C` at 1 atm pressure, benzene- toluene form an ideal solution.

Explanation

To find the mole fraction of benzene in a benzene-toluene mixture that will boil at 88°C and 1 atm pressure, we will use Raoult's Law. Here's a step-by-step solution:

### Step 1: Understand the Given Data
- Vapor pressure of benzene (P_B°) at 88°C = 900 torr
- Vapor pressure of toluene (P_T°) at 88°C = 360 torr
- Total pressure (P_T) at which the solution boils = 1 atm = 760 torr

### Step 2: Apply Raoult's Law
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