A solution containing`8.6` urea in one litre was found to be isotonic with a `5%`(wt./vot.)solution of an organic non-volatile solute. The molecular weight of latter is:

Explanation

To solve the problem, we need to find the molecular weight of the organic non-volatile solute that is isotonic with a solution containing 8.6 grams of urea in 1 liter. We will use the concept of osmotic pressure and the relationship between the concentrations of the two solutions.

### Step-by-Step Solution:

1. **Understanding Isotonic Solutions**:
- For two solutions to be isotonic, their osmotic pressures must be equal. This means that:
\[
\Pi_1 = \Pi_2
...