The products of reaction of alcoholic silver nitrite with enthyl bromide are

Options

A. Ethane
B. Ethene
C. Ethyl alcohol
D. Nitro ethane

Answer

To solve the question regarding the products of the reaction of alcoholic silver nitrite with ethyl bromide, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this reaction are alcoholic silver nitrite (AgNO2) and ethyl bromide (C2H5Br).

2. **Understand the Nature of the Reactants**:
- Ethyl bromide is a polar molecule due to the presence of the bromine atom, which is more electronegative than carbon. This creates a partial positive charge on the ethyl group (C2H5) and a partial negative charge on the bromine atom.
- Silver nitrite is a covalent compound, which means it does not have a formal charge but has polar characteristics due to the electronegativity of oxygen and nitrogen.

3. **Mechanism of Reaction**:
- The nitrogen atom in silver nitrite (AgNO2) acts as a nucleophile due to the availability of its lone pair of electrons.
- The nucleophilic nitrogen attacks the electrophilic carbon in ethyl bromide, leading to the displacement of the bromine atom.

4. **Formation of Products**:
- The reaction leads to the formation of nitroethane (C2H5NO2) as the primary product. The bromine atom is displaced, forming silver bromide (AgBr) as a byproduct.
- The reaction can be summarized as:
\[ C2H5Br + AgNO2 \rightarrow C2H5NO2 + AgBr \]

5. **Final Products**:
- The main product of the reaction is nitroethane (C2H5NO2).
- Other potential products such as ethane (C2H6), ethene (C2H4), and ethyl alcohol (C2H5OH) are not formed in significant amounts under these reaction conditions.

### Conclusion:
The main product of the reaction of alcoholic silver nitrite with ethyl bromide is **nitroethane (C2H5NO2)**.