Ethylidene chloride can be prepared by the reaction of `HCl` and

Options

A. Ethane
B. Ethylene
C. Acetylene
D. Ethylene glycol

Answer

To solve the question regarding the preparation of ethylidene chloride from HCl, we will analyze the options provided and determine the correct reactant.

### Step-by-Step Solution:

1. **Understanding Ethylidene Chloride**:
- Ethylidene chloride is a geminal dihalide, which means it has two halogen atoms (in this case, chlorine) attached to the same carbon atom. The structure can be represented as:
```
Cl
|
H2C=C
|
Cl
```

2. **Identifying the Reactants**:
- The question states that ethylidene chloride can be prepared by the reaction of HCl with one of the given options. The options are:
- a) Ethane
- b) Ethylene
- c) Acetylene
- d) Ethylene glycol

3. **Analyzing Each Option**:
- **Ethane (C2H6)**: Ethane is a saturated hydrocarbon and does not have a double bond. It cannot react with HCl to form a geminal dihalide.
- **Ethylene (C2H4)**: Ethylene is an alkene with a double bond. It can react with HCl to form chloroethane, but not directly ethylidene chloride.
- **Acetylene (C2H2)**: Acetylene is an alkyne with a triple bond. When it reacts with 2 moles of HCl, it can form ethylidene chloride (geminal dihalide).
- **Ethylene Glycol (C2H6O2)**: Ethylene glycol is a diol and does not directly participate in the formation of ethylidene chloride with HCl.

4. **Conclusion**:
- The correct answer is **c) Acetylene**. Acetylene (ethyne) reacts with HCl to produce ethylidene chloride.

### Final Answer:
Ethylidene chloride can be prepared by the reaction of HCl and **Acetylene**.