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1-phenyl-2-chloropropane on treating wit...

1-phenyl-2-chloropropane on treating with alc. `KOH` gives mainly

A

1-phenylpropene

B

2-phenylpropene

C

1-phenylpropane-2-ol

D

1-phenylpropane-1-ol

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The correct Answer is:
To solve the question regarding the reaction of 1-phenyl-2-chloropropane with alcoholic KOH, we will follow these steps: ### Step 1: Identify the Structure of 1-Phenyl-2-chloropropane 1-Phenyl-2-chloropropane has the following structure: - The phenyl group (C6H5) is attached to the first carbon. - The second carbon has a chlorine atom (Cl) attached to it. - The third carbon is a methyl group (CH3). The structure can be represented as: ``` C6H5 | CH2-CH-CH3 | Cl ``` ### Step 2: Understand the Reaction with Alcoholic KOH When an alkyl halide like 1-phenyl-2-chloropropane reacts with alcoholic KOH, a dehydrohalogenation reaction occurs. This reaction involves the elimination of a hydrogen halide (HCl in this case) to form an alkene. ### Step 3: Determine the Mechanism of Elimination In the elimination reaction: - The hydrogen atom is removed from the beta carbon (the carbon adjacent to the one with the halogen). - The halogen (Cl) is removed from the alpha carbon (the carbon with the halogen). ### Step 4: Identify the Beta Carbons In 1-phenyl-2-chloropropane, there are two beta carbons: 1. The carbon adjacent to the phenyl group (C2). 2. The carbon that is part of the methyl group (C3). ### Step 5: Analyze the Stability of the Carbocation When the elimination occurs, a carbocation intermediate is formed. The stability of this carbocation is influenced by resonance from the phenyl group: - The carbocation formed by removing H from the beta carbon adjacent to the phenyl group (C2) is more stable due to resonance stabilization. ### Step 6: Write the Product of the Reaction The elimination will predominantly occur from the more stable carbocation, leading to the formation of: - 1-phenylpropene (C6H5-CH=CH-CH3). ### Step 7: Conclusion The main product formed when 1-phenyl-2-chloropropane reacts with alcoholic KOH is **1-phenylpropene**. ### Final Answer 1-phenylpropene is the main product. ---
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ALLEN-ALKYL AND ARYL HALIDE-EXERCISE
  1. The reaction , CH(3)Br +OH^(-)rarrCH(3)OH+Br^(-) obeys the mechanism

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  2. Ethylidene chloride can be prepared by the reaction of HCl and

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  3. 1-phenyl-2-chloropropane on treating with alc. KOH gives mainly

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  4. Grignard reagent is obtained when magnesium is treated with

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  5. Ethylene reacts bromine to form-

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  6. C(2)H(4) overset(Br(2))rarr X overset(KCN)rarr Y, Y is

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  7. Reactivity order of halides for dehydrohalogenation is : -

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  8. Which of the following is least reactive in a nucleophilic substiution...

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  9. The correct reactivity order of alcohols towards H-X will be (I) CH(...

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  10. Identify 'Z' in the following reaction series, CH(3)CH(2)CH(2)Brover...

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  11. For the reaction C(2)H(5) OH + HX to C2 H(5) X + H(2)O , the order of ...

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  12. Ethyl alcohol reacts at a faster rate with HI than with HCl in forming...

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  13. What is the order of reactivity of the following compounds towards nuc...

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  14. The order of decreasing nucleophilicity of the following is

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  15. The order of decreasing S(N)1 reactivities of the halides (I )CH(3)...

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  16. Consider the following anions. (I) CF(3)-overset(O)overset(||)unders...

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  17. The basicity of RO^(-),HO^(-),RCOO^(-),ROH and H(2)O are of the order-

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  18. Which of the following are aprotic solvents:

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  19. Which is/are true statements (s):

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  20. Ph-overset(Me)overset(|)underset(H)underset(|)(C)-OH overset(SOCl(2))u...

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