Identify `'Z'` in the following reaction series,
`CH_(3)CH_(2)CH_(2)Broverset(NaOH(aq))rarr(X)overset(Al_(2)O_(3))underset(heat)rarr`
`(Y) overset(Cl_(2) //H_(2)O)rarr(Z)`

Answer

To identify 'Z' in the given reaction series, we will analyze each step of the reactions systematically.

### Step 1: Identify the starting compound
The starting compound is **CH₃CH₂CH₂Br**, which is **bromopropane** (1-bromopropane).

### Step 2: Reaction with NaOH (aq)
When bromopropane reacts with aqueous NaOH, a nucleophilic substitution reaction occurs. The hydroxide ion (OH⁻) acts as a nucleophile and attacks the carbon bonded to bromine (Br), leading to the elimination of bromine and the formation of an alcohol.

- **Reaction**:
\[ CH₃CH₂CH₂Br + NaOH \rightarrow CH₃CH₂CH₂OH + NaBr \]
- **Product X**: **1-propanol** (CH₃CH₂CH₂OH)

### Step 3: Reaction with Al₂O₃ and heat
Next, the alcohol (1-propanol) undergoes dehydration when heated in the presence of aluminum oxide (Al₂O₃). This results in the elimination of water (H₂O), forming an alkene.

- **Reaction**:
\[ CH₃CH₂CH₂OH \xrightarrow{Al₂O₃, \text{heat}} CH₃CH=CH₂ + H₂O \]
- **Product Y**: **Propene** (CH₃CH=CH₂)

### Step 4: Reaction with Cl₂ and H₂O
Finally, propene reacts with chlorine (Cl₂) in the presence of water (H₂O). The reaction of Cl₂ with water produces hypochlorous acid (HOCl), which can add across the double bond of propene.

- **Mechanism**:
The Cl atom will add to one of the carbon atoms of the double bond, while the OH group from HOCl will add to the other carbon atom. This results in the formation of a chloroalcohol.

- **Reaction**:
\[ CH₃CH=CH₂ + Cl₂ + H₂O \rightarrow CH₃CH(Cl)CH₂(OH) \]
- **Product Z**: **2-chloro-1-propanol** (CH₃CH(Cl)CH₂OH)

### Final Answer
Thus, the compound 'Z' is **2-chloro-1-propanol**.

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