Statement-I: Chloropropane has higher boiling point than chloroethane.
Because Statement-II: Haloalkanes are polar molecules.

Options

A. Statement-I is True, Statement-II is True, Statement-II is a correct explanation for Statement-I
B. Statement-I is True, Statement-II is True, Statement-II is NOT a correct explanation for Statement-I
C. Statement-I is True, Statement-II is False.
D. Statement-I is False, Statement-II is True.

Answer

To solve the question, we need to analyze both statements provided:

**Statement-I:** Chloropropane has a higher boiling point than chloroethane.

**Statement-II:** Haloalkanes are polar molecules.

### Step 1: Understanding the Compounds
- **Chloropropane (C3H7Cl)** has the structural formula CH3CH2CH2Cl.
- **Chloroethane (C2H5Cl)** has the structural formula CH3CH2Cl.

### Step 2: Compare Molecular Masses
- Calculate the molecular mass of chloropropane:
- C: 12.01 g/mol × 3 = 36.03 g/mol
- H: 1.008 g/mol × 7 = 7.056 g/mol
- Cl: 35.45 g/mol × 1 = 35.45 g/mol
- Total molecular mass of chloropropane = 36.03 + 7.056 + 35.45 = 78.536 g/mol

- Calculate the molecular mass of chloroethane:
- C: 12.01 g/mol × 2 = 24.02 g/mol
- H: 1.008 g/mol × 5 = 5.04 g/mol
- Cl: 35.45 g/mol × 1 = 35.45 g/mol
- Total molecular mass of chloroethane = 24.02 + 5.04 + 35.45 = 64.51 g/mol

### Step 3: Analyze Boiling Points
- The boiling point of a substance is influenced by its molecular mass and intermolecular forces.
- Since chloropropane has a higher molecular mass (78.536 g/mol) compared to chloroethane (64.51 g/mol), it is expected to have a higher boiling point due to stronger van der Waals forces.

### Step 4: Evaluate Statement-I
- Therefore, **Statement-I** is true: Chloropropane does have a higher boiling point than chloroethane.

### Step 5: Analyze Statement-II
- Haloalkanes, including chloropropane and chloroethane, contain carbon-halogen bonds, which are polar due to the difference in electronegativity between carbon and halogen (Cl).
- This means that **Statement-II** is also true: Haloalkanes are indeed polar molecules.

### Step 6: Determine the Relationship Between Statements
- While both statements are true, **Statement-II** does not correctly explain **Statement-I**. The boiling point is primarily influenced by molecular mass, not polarity.
- Therefore, the correct conclusion is that **Statement-I is true, Statement-II is true, but Statement-II is not the correct explanation of Statement-I.**

### Final Answer
- **Statement-I is true.**
- **Statement-II is true.**
- **Statement-II is not the correct explanation of Statement-I.**