An optically active compound A (assume dextrorotatory) has the molecular formula `C_(7)H_(11)Br`. A reacts with hydrogen bromide, in the absence of peroxides to yield isomeric products, B and C, with the molecular formula `C_(7)H_(12)Br_(2)`. Compound B is optically active, C is not. Treating B with 1 mol of potassium butoxide yields `(+)-A`. Treating C with 1 mol of potassium tert-butoxide yields `(+-)-A`. Treating A with potassium tert-butoxide yields `D(C_(7)H_(10))`. Subjecting 1 mol of `D` to ozonolysis followed by treatement with zinc and acetic acid yields 2 moles of formaldehyde and 1 mole of 1,3-cyclopentanedione.

The compound 'B' is:

Options

A.
B.
C.
D.

Answer

C