In a cell that utilises the reaction.
`Zn(s) +2H^(+)(aq) rarr Zn^(2+) (aq) +H_(2)(s)` addition of `H_(2)SO_(4)` to cathode compartement, will:
(1) increase the `E_(Cell)` and shift equilibrium to the right
(2) lower the `E_(cell)` and shift equilibrium to the right
(3) lower the `E_(cell)` and shift equilibrium to the left
(4) increase the `E_(cell)` and shift equilibrium to the left

Answer

A

Explanation

`E_(cell) = E_(cell)^(@) - (0.059)/(2)log.(1)/([H^(+)]^(2))`
On adding `H_(2)SP_(4),[H^(+)]` will increase therefore `E_(cell)` will also increase and the equilibrium will shift towards right.