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The limiting molar conductivities overse...

The limiting molar conductivities `overset(o)(wedge)` for NaCl, KBr and KCl are 126, 152 and `150 S cm^(2)mol^(-1)` respectively. The `overset(o)(wedge)` for NaBr is:

A

`278 S cm^(2) mol^(-1)`

B

`176 S cm^(2) mol^(-1)`

C

`128 S cm^(2) mol^(-1)`

D

`302 s cm^(2) mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`^^_(NaBr)^(@) = lambda_(Na)^(@) +lambda_(CI^(-))^(@) - lambda_(K^(+))^(@) +lambda_(Br^(-))^(@) - lambda_(R^(+))^(@) -lambda_(CI^(-))^(@)`
`=lambda_(NaCI)^(@) +lambda^(@) KBr - lambda^(@) KCI`
`= (126 +152 -150) S cm^(2) mol^(-1)`
`= 128 S cm^(2) mol^(-1)`
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