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Calculate the equilibrium constant for the reaction, `2Fe^(3+) + 3I^(-) hArr 2Fe^(2+) + I_3^-` . The standard reduction potentials in acidic conditions are 0.77 and 0.54 V respectively for `Fe^(3+)//Fe^(2+)` and `I_3^(-) //I^-` couples.

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The correct Answer is:
`K_(C) = 6.26 xx 10^(-7)`
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ALLEN-ELECTROCHEMISTRY-EXERCISE -05 [B]
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