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Electrolysis of dilute aqueous NaCl solu...

Electrolysis of dilute aqueous `NaCl` solution was carried out by passing `10mA` current. The time required to liberate `0.01mol` of `H_(2)` gas at the cathode is `(1F=96500C mol ^(-1))`
(a)`9.65xx10^(4)s`
(b)`19.3xx10^(4)s`
(c)`28.95xx10^(4)s`
(d)`38.6xx10^(4)s`

A

`9.65 xx 10^(4)`sec

B

`19.3 xx 10^(4)` sec

C

`28.95 xx 10^(4)`sec

D

`38.6 xx 10^(4)`sec

Text Solution

Verified by Experts

The correct Answer is:
B
No. of Faraday of electricity ot liberate `0.01`
Mole `= 0.01 xx 2F = 0.02F`
`=2 xx 10^(-2) xx 9600 = 1930` coulomb
`A = 10` miliampere `= 0.01` ampere
`Q = 1 xx t`
`t = (Q)/(I) = (1930)/(0.01) = 1.93 xx 10^(5) = 19.3 xx 10^(4)` sec
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