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The nature of mixture obtained by mixing...

The nature of mixture obtained by mixing 50mL of `0.1M H_(2)SO_(4)` and `50mL` of `0.1M NaOh` is:

A

Acidic

B

Basic

C

Neutral

D

Amphoteric

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The correct Answer is:
To determine the nature of the mixture obtained by mixing 50 mL of 0.1 M H₂SO₄ and 50 mL of 0.1 M NaOH, we will follow these steps: ### Step 1: Calculate the number of moles of NaOH The molarity (M) is defined as the number of moles of solute (n) divided by the volume of solution in liters (V). Given: - Molarity of NaOH = 0.1 M - Volume of NaOH = 50 mL = 0.050 L Using the formula: \[ M = \frac{n}{V} \] We can rearrange it to find the number of moles: \[ n = M \times V \] Substituting the values: \[ n_{\text{NaOH}} = 0.1 \, \text{mol/L} \times 0.050 \, \text{L} = 0.005 \, \text{mol} \] ### Step 2: Calculate the number of moles of H₂SO₄ Similarly, we calculate the number of moles of H₂SO₄. Given: - Molarity of H₂SO₄ = 0.1 M - Volume of H₂SO₄ = 50 mL = 0.050 L Using the same formula: \[ n_{\text{H₂SO₄}} = M \times V \] Substituting the values: \[ n_{\text{H₂SO₄}} = 0.1 \, \text{mol/L} \times 0.050 \, \text{L} = 0.005 \, \text{mol} \] ### Step 3: Determine the number of moles of H⁺ ions from H₂SO₄ H₂SO₄ dissociates in water to produce 2 moles of H⁺ ions for every mole of H₂SO₄: \[ \text{H₂SO₄} \rightarrow 2 \text{H}^+ + \text{SO₄}^{2-} \] Thus, the number of moles of H⁺ ions is: \[ n_{\text{H}^+} = 2 \times n_{\text{H₂SO₄}} = 2 \times 0.005 \, \text{mol} = 0.010 \, \text{mol} \] ### Step 4: Determine the number of moles of OH⁻ ions from NaOH NaOH dissociates completely in water to produce 1 mole of OH⁻ ions for every mole of NaOH: \[ \text{NaOH} \rightarrow \text{Na}^+ + \text{OH}^- \] Thus, the number of moles of OH⁻ ions is: \[ n_{\text{OH}^-} = n_{\text{NaOH}} = 0.005 \, \text{mol} \] ### Step 5: Compare the number of moles of H⁺ and OH⁻ Now we compare the number of moles of H⁺ and OH⁻: - Moles of H⁺ = 0.010 mol - Moles of OH⁻ = 0.005 mol Since the number of moles of H⁺ (0.010 mol) is greater than the number of moles of OH⁻ (0.005 mol), the resulting mixture will be acidic. ### Conclusion The nature of the mixture obtained by mixing 50 mL of 0.1 M H₂SO₄ and 50 mL of 0.1 M NaOH is **acidic**.

To determine the nature of the mixture obtained by mixing 50 mL of 0.1 M H₂SO₄ and 50 mL of 0.1 M NaOH, we will follow these steps: ### Step 1: Calculate the number of moles of NaOH The molarity (M) is defined as the number of moles of solute (n) divided by the volume of solution in liters (V). Given: - Molarity of NaOH = 0.1 M - Volume of NaOH = 50 mL = 0.050 L ...
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ALLEN-SOLUTIONS-EXERCISE -01
  1. The number of moles present in 2 litre of 0.5 M NaOH is:

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  2. The weight of solute present in 200mL of 0.1M H(2)SO(4):

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  3. The nature of mixture obtained by mixing 50mL of 0.1M H(2)SO(4) and 50...

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  4. If 250 mL of a solution contains 24.5 g H(2)SO(4) the molarity and nor...

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  5. The volume strength of H(2)O(2) solution is 10. what does it mean:

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  6. The normality of 0.3 M phosphorous acid (H(3) PO(3)) is

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  7. The normally of 4% (wt/vol).NaOH is:

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  8. The density of NH(4)OH solution is 0.6g//mL. It contains 34% by weigh...

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  9. A molal solution is one that contains one mole of a solute in:

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  10. Define the terms: (i) Molarity (ii) Molality (iii) Normality (iv) Mo...

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  11. 3.0 molal NaOH solution has a density of 1.110 g/ml. The molarity of t...

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  12. 1000 gram aqueous solution of CaCO(3) contains 10 gram of carbonate. C...

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  13. When 0.5 gram of BaCI(2) is dissolved in water to have 10^(6) gram of ...

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  14. How many grams of glucose be dissolved to make one litre solution of 1...

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  15. Vapour pressure of a solvent containing nonvolatile solute is:

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  16. The relative lowering in vapour pressure is:

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  17. The vapour pressure of a dilute solution of a solute is influeneced by...

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  18. An aqueous solution of methanol in water has vapour pressure

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  19. When a substance is dissolved in a solvent the vapour pressure of solv...

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  20. Solute when dissolved in water:

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