When `0.5` gram of `BaCI_(2)` is dissolved in water to have `10^(6)` gram of solution. The concentration of solution is:

Options

A. 2.5 ppm
B. 5 ppm
C. `5M`
D. `5gL^(-1)`

Explanation

To find the concentration of the solution in parts per million (ppm), we can follow these steps:

### Step 1: Understand the Components
We have:
- Mass of BaCl₂ (solute) = 0.5 grams
- Mass of the solution = \(10^6\) grams

### Step 2: Use the PPM Formula
The formula for parts per million (ppm) is given by:

\[ \text{ppm} = \left( \frac{\text{mass of solute}}{\text{mass of solution}} \right) \times 10^6 \]

### Step 3: Substitute the Values
Now, we can substitute the values into the formula:

\[ \text{ppm} = \left( \frac{0.5 \text{ g}}{10^6 \text{ g}} \right) \times 10^6 \]

### Step 4: Calculate the Concentration
Now, perform the calculation:

\[ \text{ppm} = \left( \frac{0.5}{10^6} \right) \times 10^6 = 0.5 \]

### Step 5: Final Result
Thus, the concentration of the solution is:

\[ \text{Concentration} = 0.5 \text{ ppm} \]