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How many grams of glucose be dissolved t...

How many grams of glucose be dissolved to make one litre solution of `10%1` glucose:

A

`10g`

B

`180g`

C

`100g`

D

`1.8g`

Text Solution

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The correct Answer is:
To determine how many grams of glucose need to be dissolved to make a 1-liter solution of 10% glucose, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Definition of Percentage Concentration**: A 10% glucose solution means that there are 10 grams of glucose in every 100 mL of solution. 2. **Convert Liters to Milliliters**: Since we need to prepare a 1-liter solution, we convert liters to milliliters: \[ 1 \text{ liter} = 1000 \text{ mL} \] 3. **Use the Unitary Method**: We know that in 100 mL of solution, there are 10 grams of glucose. We want to find out how many grams are in 1000 mL (1 liter). \[ \text{If } 100 \text{ mL contains } 10 \text{ grams, then } 1000 \text{ mL will contain } x \text{ grams.} \] We can set up a proportion: \[ \frac{10 \text{ grams}}{100 \text{ mL}} = \frac{x \text{ grams}}{1000 \text{ mL}} \] 4. **Cross-Multiply to Solve for x**: \[ 10 \text{ grams} \times 1000 \text{ mL} = x \text{ grams} \times 100 \text{ mL} \] \[ 10000 = 100x \] 5. **Isolate x**: \[ x = \frac{10000}{100} = 100 \text{ grams} \] 6. **Conclusion**: To prepare a 1-liter solution of 10% glucose, you need to dissolve **100 grams of glucose**. ### Final Answer: 100 grams of glucose. ---

To determine how many grams of glucose need to be dissolved to make a 1-liter solution of 10% glucose, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Definition of Percentage Concentration**: A 10% glucose solution means that there are 10 grams of glucose in every 100 mL of solution. 2. **Convert Liters to Milliliters**: ...
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Knowledge Check

  • A solution containing 10.2 g of glycrine per litre is found to be isotonic with 2% solution of glucose ("molar mass"=180 g mol^(-1)) . Calculate the molar mass of glycrine.

    A
    91.8 g
    B
    1198 g
    C
    83.9 g
    D
    890.3 g
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