The boiling point of `C_(6)H_(6), CH_(3)OH, C_(6)H_(5)NH_(2)` and `C_(6)H_(5)NO_(2)` are `80^(@)C, 65^@ C ,184^@ C` and `212^(@)C` respectively. Which will show highest vapour pressure at room temerature:

Options

A. `C_(6)H_(6)`
B. `CH_(3)OH`
C. `C_(6)H_(5)NH_(2)`
D. `C_(6)H_(5)NO_(@)`

Explanation

To determine which compound will show the highest vapor pressure at room temperature based on the given boiling points, we can follow these steps:

### Step 1: Understand the relationship between boiling point and vapor pressure
Boiling point and vapor pressure have an inverse relationship. This means that a lower boiling point corresponds to a higher vapor pressure, and vice versa.

### Step 2: List the boiling points of the compounds
- C6H6 (Benzene): 80°C
- CH3OH (Methanol): 65°C
- C6H5NH2 (Aniline): 184°C
- C6H5NO2 (Nitrobenzene): 212°C

### Step 3: Identify the lowest boiling point
From the listed boiling points, we can see that:
- The lowest boiling point is that of CH3OH (Methanol) at 65°C.

### Step 4: Determine which compound has the highest vapor pressure
Since CH3OH has the lowest boiling point, it will have the highest vapor pressure at room temperature according to the inverse relationship between boiling point and vapor pressure.

### Conclusion
Thus, the compound that will show the highest vapor pressure at room temperature is **CH3OH (Methanol)**.

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