Which solution will show maximum elevation in b.pt:

Options

A. `0.1M KCI`
B. `0.1M BaCI_(2)`
C. `0.1M FeCI_(3)`
D. `0.1MFe_(@)(SO_(4))_(3)`

Explanation

To determine which solution will show the maximum elevation in boiling point, we need to analyze the van't Hoff factor (i) for each of the given compounds. The van't Hoff factor is the number of particles (ions or molecules) that a solute produces when it dissolves in a solvent. The elevation in boiling point is directly proportional to this factor.

### Step-by-Step Solution:

1. **Identify the Compounds:**
We have the following compounds to analyze:
- KCl
- BaCl2
- FeCl3
- Fe2(SO4)3

2. **Calculate the van't Hoff factor (i) for each compound:**
- **For KCl:**
- Dissociation: KCl → K⁺ + Cl⁻
- Number of particles = 2
- Therefore, i = 2.

- **For BaCl2:**
- Dissociation: BaCl2 → Ba²⁺ + 2Cl⁻
- Number of particles = 3
- Therefore, i = 3.

- **For FeCl3:**
- Dissociation: FeCl3 → Fe³⁺ + 3Cl⁻
- Number of particles = 4
- Therefore, i = 4.

- **For Fe2(SO4)3:**
- Dissociation: Fe2(SO4)3 → 2Fe³⁺ + 3SO4²⁻
- Number of particles = 5
- Therefore, i = 5.

3. **Compare the van't Hoff factors:**
- KCl: i = 2
- BaCl2: i = 3
- FeCl3: i = 4
- Fe2(SO4)3: i = 5

4. **Determine the maximum elevation in boiling point:**
The solution with the highest van't Hoff factor will show the maximum elevation in boiling point. From our calculations, Fe2(SO4)3 has the highest i value of 5.

### Conclusion:
The solution that will show the maximum elevation in boiling point is **Fe2(SO4)3**.

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