The boiling point of an aqueous solution of a non-volatile solute is `100.15^(@)C`. What is the freezing point of an aqueous solution obtained by dilute the above solution with an equal volume of water. The values of `K_(b)` and `K_(f)` for water are `0.512` and `1.86^(@)C mol^(-1)`:

Options

A. `-0.544^(@)C`
B. `-0.512^(@)C`
C. `-0.272^(@)C`
D. `-1.86^(@)C`

Answer

C

Explanation

`0.15 = 0.512 xm, m' = (1)/(2) ((0.15)/(0.512))`
`DeltaT_(f) = 1.86 xx (0.15)/(0.512) xx (1)/(2)`
`T_(f) =- 0.272^(@)C`