Two solution of a substance (non electrolyte) are mixed in the following manner:
480 mL of 1.5 M first solution +520 mL of 1.2 M second solution.
What is the molarity of the final mixture?

Options

A. `1.50M`
B. `1.20M`
C. `2.70M`
D. `1.344M`

Answer

D

Explanation

`M = (M_(1)U_(1)+M_(2)U_(2))/(V_(f)) = (M_(1)U_(1)+M_(2)U_(2))/(V_(1)+V_(2))`
`= (1.5 xx 0.48 +1.2 xx 0.52)/(1)`
`= 0.72 +0.624`
`= 1.344 M`