K(f) for water is 1.86 K kg mol^(-1). If...

`K_(f)` for water is `1.86 K kg mol^(-1)`. If your automobile radiator holds `1.0 kg` of water, how many grams of ethylene glycol `(C_(2)H_(6)O_(2))` must you add to get the freezing point of the solution lowered to `-2.8^(@)C` ?

A

`27g`

B

`72g`

C

`93g`

D

`39g`

Text Solution

Verified by Experts

The correct Answer is:

C

`2.8 = 1.86 xx (w//62)/(1) rArr w = 93.33gm`

Topper's Solved these Questions

SOLUTIONS
ALLEN|Exercise EXERCISE -05 [B]|22 Videos
SOLUTIONS
ALLEN|Exercise EXERCISE-04 [B]|20 Videos
S-BLOCK ELEMENTS
ALLEN|Exercise EXERCISE -3|1 Videos
Some Basic Concepts of Chemistry (Mole concept)
ALLEN|Exercise All Questions|39 Videos

Similar Questions

Explore conceptually related problems

45 g of ethylene glycol (C_(2) H_(6)O_(2)) is mixed with 600 g of water. The freezing point of the solution is (K_(f) for water is 1.86 K kg mol^(-1) )

The freezing point of 0.05 m solution of glucose in water is (K1 = 1.86°C m^(-1) )

45 g of ethylene glycol C_(2)H_(6)O_(2) is mixed with 600 g of water. Calculate (a) the freezing point depression and (b) the freezing point of solution. Given K_(f)=1.86 K kg mol^(-1) .

0.1 mole of sugar is dissolved in 250 g of water. The freezing point of the solution is [K_(f) "for" H_(2)O = 1.86^(@)C "molal"^(-1)]

If 0.1 m aqueous solution of calcium phosphate is 80% dissociated then the freezing point of the solution will be (K_f of water = 1.86K kg mol^(-1))

45 g of ethylene glycol C_(2)H_(4)O_(2) is mixed with 600 g of water. Calculate (a) the freezing point depression and (b) the freezing point of solution. Given K_(f)=1.86 K kg mol^(-1) .

A 0.1 molal aqueous solution of a weak acid is 30% ionized. If K_(f) for water is 1.86^(@)C//m , the freezing point of the solution will be.

In a 2.0 molal aqueus solution of a weak acid HX the degree of disssociation is 0.25. The freezing point of the solution will be nearest to: ( K_(f)=1.86 K kg "mol"^(-1) )

The molal freezing point constant of water is 1.86 K m^(-1) . If 342 g of cane sugar (C_(12)H_(22)O_(11)) is dissolved in 1000 g of water, the solution will freeze at

How many grams of methyl alcohol should be added to 10 litre tank of water to prevent its freezing at 268K ? (K_(f) for water is 1.86 K kg mol^(-1))

ALLEN-SOLUTIONS-EXERCISE-05 [A]

A 5% (w/V ) solution of cane sugar (molecular mass = 342) is isotonic ...
Text Solution
|
The molality of a urea solution in which 0.0100 g of urea, [(NH2)2 CO]...
Text Solution
|
K(f) for water is 1.86 K kg mol^(-1). If your automobile radiator hold...
Text Solution
|
The freezing point of a 1.00 m aqueous solution of HF is found to be -...
Text Solution
|
Two liquids A and B form an ideal solution. At 300 K, the vapour press...
Text Solution
|
A solution containing 0.85 g of ZnCl(2) in 125.0g of water freezes at ...
Text Solution
|
A solution containing 0.85 g of ZnCI(2) in 125.0g of water freezes at ...
Text Solution
|
12g of a nonvolatile solute dissolved in 108g of water produces the re...
Text Solution
|
A molecule M associates in a given solvent according to the equation M...
Text Solution
|
Vapour pressure of pure benzene is 119 torr and that of toluene is 37....
Text Solution
|
How many grams of methyl alcohol should be added to 10 litre tank of w...
Text Solution
|
Consider separate solutions of 0.500 M C(2)H(5)OH(aq),0.100 M Mg(3)(PO...
Text Solution
|
For an ideal solution of two components A and B, which of the followin...
Text Solution
|
The observed osmotic pressure for a 0.10M solution of Fe(NH(4))(2)(SO(...
Text Solution
|
The vapour pressure of acetone at 20^(@)C is 185 torr. When 1.2 g of n...
Text Solution
|
A solution at 20^(@)C is composed of 1.5 mol of benzene and 3.5 mol o...
Text Solution
|
Determination of the molar mass of acetic acid in benzene using freezi...
Text Solution
|
18 g glucose (C(6)H(12)O(6)) is added to 178.2 g water. The vapour pre...
Text Solution
|
The solubility of N(2) in water at 300K and 500 torr partial pressure ...
Text Solution
|
An aqueous solution of a salt MX(2) at certain temperature has a van'f...
Text Solution
|