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The elevation in boiling point for 13.44...

The elevation in boiling point for 13.44 g of `CuCl_(2)` dissolved in 1 kg of water as solvent will be `(K_(b) = -0.52 K m^(-1), "molar mass of" CuCl_(2) = 134.4 g mol^(-1))`

A

`0.05`

B

`0.1`

C

`0.16`

D

`0.21`

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaT_(b) = iK_(b) m`
`=3 x 0.52 xx (13.44//134.4)/(1)`
`= 0.156 K`
`=0.16K`
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