A compound `H_(2)X` with molar weight of 80 g is dissolved in solvent having density of `0.4 gm L^(-1)`. Assuming no change in volume upon dissolution, the molality of a 3.2 molar solution is :

Answer

8

Explanation

Molarity `= 3.2 M`
Let volume of solution `= 1000 ml =` volume of solvent
Mass of solvent `= 1000 xx 0.4 = 400 gm`
`m_(solute) = 3.2` mole
Molality (m) `=(3.2)/(400//1000) = 8`