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A rubber cube of side 5 cm has one side ...

A rubber cube of side `5 cm` has one side fixed while a tangential force equal to `1800 N` is applied to opposite face. Find the shearing strain and the lateral displacement of the strained face. Modulus of rigidity for rubber is `2.4 xx 10^(6) N//m^(2)`.

Text Solution

Verified by Experts

Stress `=(F)/(A)=eta(x)/(L)`
strain `=theta=(F)/(Aeta)=(1800)/(25xx10^(-4)xx2.4xx10^(6))=(180)/(25xx24)=(3)/(10)=0.3rad`
as `(x)/(L)=0.3impliesx=0.3xx5xx10^(-2)m=1.5mm`
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