Home
Class 11
PHYSICS
When composite rod is free, then composi...


When composite rod is free, then composite length increases to 2.002 m for temperature `20^(@)C` to `120^(@)C` when composite rod is fixed between the support there is no change in component length find y and `alpha` of steel, if `y_(c)=1.5xx10^(13)N//m^(2)alpha_(c)=1.6xx10^(-5)//.^(@)C`.

Text Solution

Verified by Experts

`Deltal=l_(S)alpha_(S)DeltaT+l_(C)alpha_(C)DeltaTimplies0.002=[1.5alpha_(S)+0.5xx1.6xx10^(-5)]xx100`
`impliesalpha_(S)=(1.2xx10^(-5))/(1.5)=8xx10^(-6)// .^(@)C`
there is no change in compoenent length
Promotional Banner

Topper's Solved these Questions

  • ELASTICITY, SURFACE TENSION AND FLUID MECHANICS

    ALLEN|Exercise Exercise 1 (Elasticity)|16 Videos

  • ELASTICITY, SURFACE TENSION AND FLUID MECHANICS

    ALLEN|Exercise Exercise 1 (Surface Tension)|21 Videos

  • CENTRE OF MASS

    ALLEN|Exercise EXERCISE-V B|19 Videos

  • ERROR AND MEASUREMENT

    ALLEN|Exercise Part-2(Exercise-2)(B)|22 Videos

Similar Questions

Explore conceptually related problems

When composite rod is free, composite length increase to 2.002m from temperature 20^(@)C to 120^(@)C . When composite rod is fixed between the support, there is no change in component length. Find Y and alpha of steel if Y_(cu) = 1.5 xx 10^(13) N//m^(2) and alpha_(cu) = 1.6 xx 10^(-5//@)C

A steel wire is heated to 170^(@)C and held between two rigid supports which are 20cm apart. The wire is allowed to cool to a temperature of 29.6^(@)C . If the frequency of the note produced when the wire is plucked at the middle is 100 k , then find the value of k . (The density D of steel is 7.8xx10^(3)kg//m^(3) and for steel alpha=16xx10^(-6)K^(-1) and Y of steel =20xx10^(10)Pa .).

A wire 3 m is length and 1 mm is diameter at 30^(@) C is kept in a low temperature at -170^(@)C and is stretched by hanging a weight of 10 kg at one end. The change in length of the wire is [Take, Y=2xx10^(11) N//m^(2), g=10 m//s^(2) and alpha =1.2 xx 10^(-5) //""^(@)C ]

What is the percentage change in length of 1m iron rod it its temperature changes by 100^(@)C. alpha for iron is 2 xx 10^(-5)//"^(@)C .

A rod of length 2 m is at a temperature of 20^@ C. find the free expansion of the rod, if the temperature is increased to 50^@ C, then find stress produced when the rod is (i) fully prevented to expand, (ii) permitted to expand by 0.4mm. Y=2xx10^(11)N//m^(2), alpha=15xx10^(-6//^(@))C .

A steel tape measures that length of a copper rod as 90.0 cm when both are at 10^(@)C , the calibration temperature, for the tape. What would the tape read for the length of the rod when both are at 30^(@)C . Given alpha_("steel")=1.2xx10^(-5)" per".^(@)Cand alpha_(Cu)=1.7xx10^(-5)per .^(@)C

Two rods of equal cross sections, one of copper and the other of steel, are joined to form a composite rod of length 2.0 m at 20^@C , the length of the copper rod is 0.5 m. When the temperature is raised to 120^@C , the length of composite rod increases to 2.002m. If the composite rod is fixed between two rigid walls and thus not allowed to expand, it is found that the lengths of the component rods also do not change with increase in temperature. Calculate Young's moulus of steel. (The coefficient of linear expansion of copper, alpha_c=1.6xx10^(-5@)C and Young's modulus of copper is 1.3xx10^(13)N//m^(2) ).

A steel rod of length 6.0 m and diameter 20 mm is fixed between two rigid supports . Determine the stress in the rod, when the temperature increases by 80^@ C if (a)the ends do not yield (b) the ends yield by 1mm Take Y=2.0xx10^(6) kg//cm^(2) and alpha=12xx10^(-6) per ^@C.

What must be the lengths of steel and copper rods at 0^(@)C for the difference in their lengths to be 10 cm at any common temperature? (alpha_(steel)=1.2xx10^(-5).^(@)K^(-1)and alpha_("copper")=1.8xx10^(-5).^(@)K^(-1))

A surveyor uses a steel measuring tape that is exactly 50.000 m long at a temperature of 20^(@)C What is its length on a hot summer day when the temperature is 35^(@)C ? (alpha_("steel")=1.2xx10^(-5)K^(-1))