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A rubber ball of mass 10 gram and volume...

A rubber ball of mass 10 gram and volume `15 cm^3` is dipped in water to a depth of 10m. Assuming density of water uniform throughout the depth, find the acceleration of the ball `("Take g" =980 cm//s^2)`

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AI Generated Solution

To find the acceleration of the rubber ball when it is dipped in water, we can follow these steps: ### Step 1: Identify the given data - Mass of the rubber ball, \( m = 10 \) grams = \( 0.01 \) kg (since 1 gram = 0.001 kg) - Volume of the rubber ball, \( V = 15 \) cm³ = \( 15 \times 10^{-6} \) m³ (since \( 1 \) cm³ = \( 10^{-6} \) m³) - Depth of water, \( h = 10 \) m - Density of water, \( \rho = 1000 \) kg/m³ (standard value) - Acceleration due to gravity, \( g = 980 \) cm/s² = \( 9.8 \) m/s² ...
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