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A drop of water of radius 0.0015 mm is f...

A drop of water of radius `0.0015 mm` is falling in air. If the coefficient of viscosity of air is `1.8 xx 10^(-5)kg//ms`, what will be the terminal velocity of the drop? Density of water `= 1.0 xx 10^(3) kg//m^(3)` and `g = 9.8 N//kg`. Density of air can be neglected.

Text Solution

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`V_(T)=(2)/(9)(r^(2)(rho-sigma)g)/(eta)=(2xx[(15xx10^(-4))/(1000)]^(2)xx10^(3)xx9.8)/(9xx1.8xx10^(-5))=2.72xx10^(-4)m//s`
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