A body of volume 100 c.c. is immersed completely in waer contained in a jar. The weight of water and the jar before immersion of the body was 700g wt. after immersion weight of water and jar will be

Options

A. 700 g wt
B. 800 g wt.
C. 500 g wt
D. 100 g wt

Answer

To solve the problem step by step, we will analyze the situation before and after the immersion of the body in the water.

### Step 1: Understand the initial conditions
Before the body is immersed in the water, the weight of the water and the jar is given as 700 g wt. This is our starting point.

### Step 2: Determine the volume of the body
The body has a volume of 100 c.c. Since 1 c.c. of water has a mass of 1 g, the mass of the water displaced by the body when it is immersed is equal to the volume of the body in grams. Therefore, the body displaces 100 g of water.

### Step 3: Apply Archimedes' Principle
According to Archimedes' Principle, the weight of the fluid displaced by the body is equal to the upthrust (or buoyant force) acting on the body. In this case, the upthrust force is equal to the weight of the water displaced, which is 100 g wt.

### Step 4: Calculate the total weight after immersion
After the body is immersed in the water, the total weight of the water and jar will be the initial weight plus the weight of the water displaced (upthrust). Therefore, the total weight after immersion is:
\[ \text{Weight after immersion} = \text{Initial weight} + \text{Weight of water displaced} \]
\[ \text{Weight after immersion} = 700 \, \text{g wt} + 100 \, \text{g wt} = 800 \, \text{g wt} \]

### Final Answer
The weight of the water and the jar after immersion of the body will be **800 g wt**.

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