Length of the horizontal arm of a uniform cross - section U - tube is l = 5 cm and both ends of the vertical arms are open to the surrounding pressure of `"7700 N m"^(-2)`. A liquid of density `rho=10^(3)" kg m"^(-3)` is poured into the tube such that the liquid just fills the horizontal part of the tube. Now, one of the open ends is sealed and the tube. Now, one of the open ends is sealed and the tube is then rotaed about a vertical axis passing through the other veritcal arm with angular velocity `omega` due to which the liquid rises up to half the length of the vertical arm. If length of each vertical arm is a = 6 cm. What is the value of `omega("in rad s"^(-1))`?

Answer

`5cm`