Home
Class 12
PHYSICS
In the given figure L=1 metre if total g...


In the given figure `L=1` metre if total gravitational force on 4 kg mass is `verF_(1)` and on 2 kg mass is `vecF_(2)` then find out the ratio of `|(vecF_(2))/(vecF_(2))|`

Text Solution

Verified by Experts

The correct Answer is:
`sqrt(2)`
`F_(1)=|F_(42)+vecF_(41)+vecF_(41)|`
`=(G8)/(4L^(2))+(G4)/(2L^(2))(2cos45)=((2+2sqrt(2))G)/(L^(2))`
`F_(2)=|vecF_(24)+vecF_(21)+vecF_(21)|=(G8)/(4L^(2))+(G2)/(2L^(2))(2cos45)`
`=(G)/(L^(2))(2+sqrt(2))implies(F_(1))/(F_(2))=sqrt(2)`
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    ALLEN|Exercise Exercise 4 B (Brain Storming Subjective Exercise)|20 Videos

  • GRAVITATION

    ALLEN|Exercise Exercise 5 A (Previous Year Questions)|26 Videos

  • GRAVITATION

    ALLEN|Exercise Exercise 3 (Miscellaneous Type Questions)|20 Videos

  • GEOMETRICAL OPTICS

    ALLEN|Exercise subjective|14 Videos

  • KINEMATICS-2D

    ALLEN|Exercise Exercise (O-2)|46 Videos

Similar Questions

Explore conceptually related problems

Find the acceleration of 3 kg mass when acceleration of 2 kg mass is 2ms^(-2) as shown in figure-2.140

In the given figure tension at the mid-point of string -2 . If mass of string -1 is 6 kg and mass of string -2 is 4 kg .

The gravitational force between two stones of mass 1 kg each separted by a distance of 1 metre in vaccum is

Which would requires a greater force: accelerating a 2kg mass at 5m//s^(2) or a 4kg mass at 2m//s^(2) ?

In the figure shown the man of mass 60kg is lowering a block of mass 10kg with an acceleration of 2m//s^2 . Find the reading of the machine.

In the figure shown the man of mass 60kg is lowering a block of mass 10kg with an acceleration of 2m//s^2 . Find the reading of the machine.

For the given figure the acceleration of 1 kg block if string is massless and mass of pulley is 2 kg and diameter of pulley is 0.2 m :-

The figure shows a horizontal force vecF acting on a block of mass M on an inclined plane (angle theta ). What is the normal reaction N on the block?

Resultant of two forces vecF_(1) and vecF_(2) has magnitude 50 N. The resultant is inclined to vecF_(1) at 60^(@) and to vecF_(1) at 30^(@) . Magnitudes of vecF_(1) and vecF_(2) , respectively, are:

The resultant of the forces vecF_(1) = 4hati-3hatj and vecF_(2) = 6hati + 8hatj is