The gravitational field in a region is givne by `vecE= (3hati - 4hatj)N//kg` Find out the work done (in joule) in displacting a particle of mass `1kg 1m` along the line `4y = 3x + 9` .

Answer

0

Explanation

For the line `4y=3x+9`
`4dy+3dx,4dy-3dx=0` ..(i)
For work in the region
`dW=vecE.(dxhati+dyhatj)=(3hati-4hatj).(dxhati+dyhatj)`
`=3dx-4dy` (from equation (i)) =0