The time period of a satellite of the earth is 5h. If the separation between the centre of earth and the satellite is increased to four times the previous value, the new time period will become.

Options

A. 10 h
B. 80 h
C. 40 h
D. 20 h

Answer

C

Explanation

`becauseTpropR^(3//2)`
`thereforeT_(2)=T_(1)((R_(2))/(R_(1)))^(3//2)=5h(4)^(3//2)=40h`