A double slit is illuminated by light of wave length 6000 Å. The slit are 0.1 cm apart and the screen is placed one metre away. Calculate.
(i). The angular position of the `10^(th)` maximum in radian and
(ii). Separation of the two adjacent minimal.

Explanation

To solve the problem step by step, we will break it down into two parts as per the question.

### Given Data:
- Wavelength (λ) = 6000 Å = \(6000 \times 10^{-10}\) m = \(6 \times 10^{-7}\) m
- Distance between slits (d) = 0.1 cm = \(0.1 \times 10^{-2}\) m = \(1 \times 10^{-3}\) m
- Distance to screen (D) = 1 m
- Order of maximum (n) = 10

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