In Young's double slit experiment, the distnace between two sources is `0.1//pimm`. The distance of the screen from the source is 25 cm. Wavelength of light used is `5000Å` Then what is the angular position of the first dark fringe.?

Explanation

To solve the problem of finding the angular position of the first dark fringe in Young's double slit experiment, we can follow these steps:

### Step 1: Identify the given values
- Distance between the two sources (slits), \(d = 0.1 \, \text{mm} = 0.1 \times 10^{-3} \, \text{m} = \frac{0.1}{\pi} \times 10^{-3} \, \text{m}\)
- Distance from the slits to the screen, \(D = 25 \, \text{cm} = 25 \times 10^{-2} \, \text{m}\)
- Wavelength of light, \(\lambda = 5000 \, \text{Å} = 5000 \times 10^{-10} \, \text{m} = 5 \times 10^{-7} \, \text{m}\)

### Step 2: Use the formula for the angular position of dark fringes
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