Figure shows the interference pattern obtained ina double-slit experiment using light of wavelength 600 m. 1, 2, 3, 4 and 5 are maked on fiv fringes.

Let `Delta X_(A)` and `Delta X_(c)` represent path difference between waves interfering at 1 and 3, respectively. Then `(|Delta X_(c)| - |Delta X_(A)|)` is equal to

Options

A. 0
B. 300 mn
C. 600 nm
D. 900 nm

Answer

B

Explanation

`CBFimplies` path difference `=0`
`DeltaX_(A)toAt" "1`
dark fringe having path difference `=(lamda)/(2)`
`DeltaX_(C)to`At 3,
bright fringes path difference `=lamda`
`therefore(|DeltaX_(C)|-|DeltaX_(A)|)=(lamda-(lamda)/(2))=(lamda)/(2)=(600)/(2)nm=300nm`