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In the Young's double slit experiment us...

In the Young's double slit experiment using a monochromatic light of wavelength `lambda,` the path difference (in terms of an integer `n`) corresponding to any point having half the peak intensity is :

A

`(2n+1)(lamda)/(2)`

B

`(2n+1)(lamda)/(4)`

C

`(2n+1)(lamda)/(8)`

D

`(2n+1)(lamda)/(16)`

Text Solution

Verified by Experts

The correct Answer is:
B
`I_("net")=I_(0)+I_(0)+2I_(0)cosphi=(I_(max))/(2)=2I_(0)impliescosphi=`
`0impliesphi=npi+(pi)/(2)=(2pi)/(lamda)Deltax impliesDeltax=(2n+1)(lamda)/(4)`
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