Light of wavelength 6000Å is incident on a slit of width 0.30 mm. The screen is placed 2 m from the slit. Find (a) the position of the first dark fringe and (b). The width of the central bright fringe.

Explanation

To solve the problem, we will break it down into two parts: (a) finding the position of the first dark fringe and (b) calculating the width of the central bright fringe.

### Given Data:
- Wavelength of light, \( \lambda = 6000 \, \text{Å} = 6000 \times 10^{-10} \, \text{m} = 6 \times 10^{-7} \, \text{m} \)
- Width of the slit, \( d = 0.30 \, \text{mm} = 0.30 \times 10^{-3} \, \text{m} = 3 \times 10^{-4} \, \text{m} \)
- Distance from the slit to the screen, \( D = 2 \, \text{m} \)

### Part (a): Position of the First Dark Fringe
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